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1985 AJHSME Problem 3

Problem

$\frac{10^7}{5\times 10^4}=$


$\text{(A)}\ .002 \qquad \text{(B)}\ .2 \qquad \text{(C)}\ 20 \qquad \text{(D)}\ 200 \qquad \text{(E)}\ 2000$

Solution

$\frac{10^7}{5\times 10^4} = \frac{10^3}{5} = \boxed{\textbf{(D)}~200}$

~ Edited by Aoum

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