Euc20191/Sub-Problem 2

Problem

What integer $a$ satisfies $3<\frac{24}{a}<4$ ?

Solution

If $a=6$ , then $\frac{24}{6}=4$ and if $a=8$ , then $\frac{24}{8}=3$ . So, $a$ has to be between $6$ and $8$ , and therefore, it has to be $\boxed{7}$ .

~Yuhao2012

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Euc20191/Sub-Problem 2

Problem

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