1983 AHSME Problems/Problem 9

Problem

In a certain population the ratio of the number of women to the number of men is $11$ to $10$ . If the average (arithmetic mean) age of the women is $34$ and the average age of the men is $32$ , then the average age of the population is

$\textbf{(A)}\ 32\frac{9}{10}\qquad \textbf{(B)}\ 32\frac{20}{21}\qquad \textbf{(C)}\ 33\qquad \textbf{(D)}\ 33\frac{1}{21}\qquad \textbf{(E)}\ 33\frac{1}{10}$

Solution

Assume, without loss of generality, that there are exactly $11$ women and $10$ men. Then the total age of the women is $34 \cdot 11 = 374$ and the total age of the men is $32 \cdot 10 = 320$ . Therefore the overall average is $\frac{374+320}{11+10} = \boxed{\textbf{(D)}\ 33\frac{1}{21}}$ .

1983 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 8	Followed by Problem 10
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1983 AHSME Problems/Problem 9

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