1996 AHSME Problems/Problem 28
Problem
On a
rectangular parallelepiped, vertices
,
, and
are adjacent to vertex
. The perpendicular distance from
to the plane containing
,
, and
is closest to
Solution
By placing the cube in a coordinate system such that
is at the origin,
,
, and
, we find that the equation of plane
is:
so
The equation for the distance of a point
to a plane
is given by:
Note that the capital letters are coefficients, while the lower case is the point itself. Thus, the distance from the origin (where
) to the plane is given by:
Since
, this number should be just a little over
, and the correct answer is
.
Note that the equation above for the distance from a point to a plane is a 3D analogue of the 2D case of the distance formula, where you take the distance from a point to a line. In the 2D case, both
and
are set equal to
.
See also
| 1996 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 27 |
Followed by Problem 29 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
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