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2000 AMC 8 Problems/Problem 21

Revision as of 19:55, 28 July 2011 by Mrdavid445 (talk | contribs) (Created page with "Keiko tosses one penny and Ephraim tosses two pennies. The probability that Ephraim gets the same number of heads that Keiko gets is <math> \text{(A)}\ \frac{1}{4}\qquad\text{(B...")
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Keiko tosses one penny and Ephraim tosses two pennies. The probability that Ephraim gets the same number of heads that Keiko gets is

$\text{(A)}\ \frac{1}{4}\qquad\text{(B)}\ \frac{3}{8}\qquad\text{(C)}\ \frac{1}{2}\qquad\text{(D)}\ \frac{2}{3}\qquad\text{(E)}\ \frac{3}{4}$

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