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1999 AMC 8 Problems/Problem 23

Revision as of 14:26, 17 June 2011 by Mrdavid445 (talk | contribs) (Created page with "Since the squares have side length <math>3</math>, the area of the entire square is <math>9</math>. The segments divide the square into 3 equal parts, so the area of each part i...")
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Since the squares have side length $3$, the area of the entire square is $9$.

The segments divide the square into 3 equal parts, so the area of each part is $3$.

The base of a triangle is $3$, so the height must be $2$.

$3-2=1$.

$CM=\sqrt 3^2+2^2$ = $\sqrt 13$

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