Art of Problem Solving

2005 AMC 12B Problems/Problem 3

Problem

A rectangle with a diagonal of length $x$ is twice as long as it is wide. What is the area of the rectangle?

$\mathrm{(A)}\ \frac14x^2      \qquad \mathrm{(B)}\ \frac25x^2      \qquad \mathrm{(C)}\ \frac12x^2      \qquad \mathrm{(D)}\ x^2      \qquad \mathrm{(E)}\ \frac32x^2$

Solution

See also