2020 AMC 8 Problems/Problem 2

Problem 2

Four friends do yardwork for their neighbors over the weekend, earning $\$15, \$20, \$25,$ and $\$40,$ respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned $\$40$ give to the others?

$\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25$

Solution

First we average $15,20,25,40$ to get $25$ . Thus, $40 - 25 = \boxed{\textbf{(C) }\$15.}$ . ~~Spaced_Out Note if you get $100 once adding it up and then /4=$ 15 or \boxed{\textbf{(C) }. $oceanxia ==Solution 2== The total earnings for the four friends is$ \$15+\$20+\$25+\$40=\$100 $. Since they decided to split their earnings equally among themselves, it follows that each person will get$ \frac{\$100}{4}=\$25 $. Since the friend who earned$ \$40 $will need to leave with$ \$25 $, he will have to give$ \$40-\$25=\$15 $to the others$ \implies\boxed{\textbf{(C) }\$15}$.
~junaidmansuri

Video Solution

https://youtu.be/-mSgttsOv2Y

~savannahsolver

2020 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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All AJHSME/AMC 8 Problems and Solutions

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2020 AMC 8 Problems/Problem 2

Contents

Problem 2

Solution

Video Solution

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