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1968 AHSME Problems/Problem 19: Difference between revisions

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== Solution ==
== Solution ==
<math>\fbox{E}</math>
<math>\fbox{E}</math>
become smart  at math and just do all the problems

Revision as of 14:19, 4 November 2018

Problem

Let $n$ be the number of ways $10$ dollars can be changed into dimes and quarters, with at least one of each coin being used. Then $n$ equals:

$\text{(A) } 40\quad \text{(B) } 38\quad \text{(C) } 21\quad \text{(D) } 20\quad \text{(E) } 19$

Solution

$\fbox{E}$

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