2004 AMC 8 Problems/Problem 1: Difference between revisions
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== Solution == | == Solution == | ||
We set up the proportion <math>\frac{12 \text{cm}}{72 \text{km}}=\frac{17 \text{cm}}{x \text{km}}</math>. Thus <math>x=102 \Rightarrow \boxed{\textbf{(B)}\ 102}</math> | We set up the proportion <math>\frac{12 \text{cm}}{72 \text{km}}=\frac{17 \text{cm}}{x \text{km}}</math>. Thus <math>x=102 \Rightarrow \boxed{\textbf{(B)}\ 102}</math> | ||
== Solution 2 == | |||
Since we know | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2004|before=First <br />Question|num-a=2}} | {{AMC8 box|year=2004|before=First <br />Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 03:18, 24 July 2018
Problem
On a map, a 
-centimeter length represents 
kilometers. How many kilometers does a 
-centimeter length represent?
Solution
We set up the proportion 
. Thus 
Solution 2
Since we know
See Also
| 2004 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
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| All AJHSME/AMC 8 Problems and Solutions | ||
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