2016 AMC 10B Problems/Problem 1: Difference between revisions
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==Solution== | ==Solution== | ||
Factorizing the numerator, <math>\frac{\frac{1}{a}\cdot(2+\frac{1}{2})}{a}</math> then becomes <math>\frac{\frac{5}{2}}{a^{2}}</math> which is equal to <math>\frac{5}{2}\cdot 2^2</math> which is <math>\textbf{(D) }10</math>. | Factorizing the numerator, <math>\frac{\frac{1}{a}\cdot(2+\frac{1}{2})}{a}</math> then becomes <math>\frac{\frac{5}{2}}{a^{2}}</math> which is equal to <math>\frac{5}{2}\cdot 2^2</math> which is <math>\boxed{\textbf{(D) }10}</math>. | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2016|ab=B|before=-|num-a=2}} | {{AMC10 box|year=2016|ab=B|before=-|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 21:07, 25 January 2018
Problem
What is the value of 
when 
?
Solution
Factorizing the numerator, 
then becomes 
which is equal to 
which is 
.
See Also
| 2016 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by - |
Followed by Problem 2 | |
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| All AMC 10 Problems and Solutions | ||
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