2017 AMC 8 Problems/Problem 5: Difference between revisions

Revision as of 14:28, 22 November 2017

What is the value of the expression $\frac{1 \cdot 2 \cdot 3 \cdot 4 \cdot 5 \cdot 6 \cdot 7 \cdot 8}{1+2+3+4+5+6+7+8}$ ?

$\textbf{(A) }1020\qquad\textbf{(B) }1120\qquad\textbf{(C) }1220\qquad\textbf{(D) }2240\qquad\textbf{(E) }3360$

We evaluate both the top and bottom: $\frac{40320}{36}$ . This simplifies to $\boxed{\textbf{(B)}\ 1120}.$

2017 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
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All AJHSME/AMC 8 Problems and Solutions

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 ==See Also==
-{{AMC8 box|year=2017|num-b=20|num-a=22}}
+{{AMC8 box|year=2017|num-b=4|num-a=6}}
 {{MAA Notice}}