2017 AMC 10B Problems/Problem 6: Difference between revisions
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==Problem== | ==Problem== | ||
What is the largest number of solid <math>2</math> | What is the largest number of solid <math>2\text{in}</math> by <math>2\text{in}</math> by <math>1\text{in}</math> blocks that can fit in a <math>3\text{in}</math> by <math>2\text{in}</math> by <math>3\text{in}</math> box? | ||
<math>\textbf{(A)}\ | <math>\textbf{(A)}\ 3\qquad\textbf{(B)}\ 4\qquad\textbf{(C)}\ 5\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 7</math> | ||
==Solution== | ==Solution== | ||
Revision as of 09:27, 16 February 2017
Problem
What is the largest number of solid
by
by
blocks that can fit in a
by
by
box?
Solution
By simply finding the volume of the larger block, we see that its area is
. The volume of the smaller block is
. Dividing the two, we see that only a maximum of
in x
in x
in blocks can fit inside a
-in by
in by
in box.
| 2017 AMC 10b (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
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