2017 AMC 10B Problems/Problem 25: Difference between revisions

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By inspection, the sequences $91,93,92,96,98,100,95$ and $93,91,92,96,98,100,95$ work, so the answer is $\boxed{\textbf{E } 100}.

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		==Cheap Solution==

		By inspection, the sequences <math>91,93,92,96,98,100,95</math> and <math>93,91,92,96,98,100,95</math> work, so the answer is $\boxed{\textbf{E } 100}.