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2017 AMC 10A Problems/Problem 1: Difference between revisions

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→Solution: The sequence is not an arithmetic sequence
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==Solution==
==Solution 1==


Notice this is the term <math>a_6</math> in a recursive sequence, defined recursively as <math>a_1 = 3, a_n = 2a_(n-1) + 1.</math> Thus:
Notice this is the term <math>a_6</math> in a recursive sequence, defined recursively as <math>a_1 = 3, a_n = 2a_{n-1} + 1.</math> Thus:
<cmath>\begin{split}
<cmath>\begin{split}
a_2 = 3*2 + 1 = 7.\\
a_2 = 3*2 + 1 = 7.\\
Line 14: Line 14:
a_4 = 15*2 + 1 = 31.\\
a_4 = 15*2 + 1 = 31.\\
a_5 = 31*2 + 1 = 63.\\
a_5 = 31*2 + 1 = 63.\\
a_6 = 63*2 + 1 = \boxed{\textbf{(C)}\ 127.}
a_6 = 63*2 + 1 = \boxed{\textbf{(C)}\ 127}
\end{split}</cmath>
\end{split}</cmath>
==Solution 2==
Starting to compute the inner expressions, we see the results are <math>1, 3, 7, 15, \ldots</math>. This is always <math>1</math> less than a power of <math>2</math>. The only admissible answer choice by this rule is thus \boxed{\textbf{(C)}\ 127}.


==See Also==
==See Also==
{{AMC10 box|year=2017|ab=A|before=First Problem|num-a=2}}
{{AMC10 box|year=2017|ab=A|before=First Problem|num-a=2}}
{{MAA Notice}}
{{MAA Notice}}

Revision as of 17:52, 8 February 2017

Problem

What is the value of $(2(2(2(2(2(2+1)+1)+1)+1)+1)+1)$?

$\textbf{(A)}\ 70\qquad\textbf{(B)}\ 97\qquad\textbf{(C)}\ 127\qquad\textbf{(D)}\ 159\qquad\textbf{(E)}\ 729$


Solution 1

Notice this is the term $a_6$ in a recursive sequence, defined recursively as $a_1 = 3, a_n = 2a_{n-1} + 1.$ Thus: \[\begin{split} a_2 = 3*2 + 1 = 7.\\ a_3 = 7 *2 + 1 = 15.\\ a_4 = 15*2 + 1 = 31.\\ a_5 = 31*2 + 1 = 63.\\ a_6 = 63*2 + 1 = \boxed{\textbf{(C)}\ 127} \end{split}\]

Solution 2

Starting to compute the inner expressions, we see the results are $1, 3, 7, 15, \ldots$. This is always $1$ less than a power of $2$. The only admissible answer choice by this rule is thus \boxed{\textbf{(C)}\ 127}.

See Also

2017 AMC 10A (Problems • Answer Key • Resources)
Preceded by
First Problem 		Followed by
Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

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