2016 AMC 8 Problems/Problem 17: Difference between revisions
Created page with "17. An ATM password at Fred's Bank is composed of four digits from <math>0</math> to <math>9</math>, with repeated digits allowable. If no password may begin with the sequence..." |
Burunduchok (talk | contribs) No edit summary |
||
| Line 1: | Line 1: | ||
17. An ATM password at Fred's Bank is composed of four digits from <math>0</math> to <math>9</math>, with repeated digits allowable. If no password may begin with the sequence <math>9,1,1,</math> then how many passwords are possible? | 17. An ATM password at Fred's Bank is composed of four digits from <math>0</math> to <math>9</math>, with repeated digits allowable. If no password may begin with the sequence <math>9,1,1,</math> then how many passwords are possible? | ||
<math>(A)\mbox{ }30\mbox{ }(B)\mbox{ }7290\mbox{ }(C)\mbox{ }9000\mbox{ }(D)\mbox{ }9990\mbox{ }(E)\mbox{ }9999\mbox{ }</math> | <math>(A)\mbox{ }30\mbox{ }(B)\mbox{ }7290\mbox{ }(C)\mbox{ }9000\mbox{ }(D)\mbox{ }9990\mbox{ }(E)\mbox{ }9999\mbox{ }</math> | ||
{{AMC8 box|year=2016|num-b=16|num-a=18}} | |||
{{MAA Notice}} | |||
Revision as of 11:25, 23 November 2016
17. An ATM password at Fred's Bank is composed of four digits from
to
, with repeated digits allowable. If no password may begin with the sequence
then how many passwords are possible?
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 16 |
Followed by Problem 18 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination