2016 AMC 8 Problems/Problem 1: Difference between revisions

Revision as of 08:59, 23 November 2016

The longest professional tennis match ever played lasted a total of $11$ hours and $5$ minutes. How many minutes was this?

$\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105$

Solution

We know that there is $60$ minutes in a hour. So, multiply $11$ and $60$ because we need to convert $11$ hours into minutes. You will get $660$ . Now, add $660$ and $5$ to get the total minutes. The answer is $\boxed{665}$

2016 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination

@@ Line 4: / Line 4: @@
 ==Solution==
-We can first convert <math>11</math> hours to minutes and then add <math>5</math> minutes. <math>11\times60=660</math> and <math>660+5=\boxed{\text{(C) }665}</math>.
+We know that there is <math>60</math> minutes in a hour.
+So, multiply <math>11</math> and <math>60</math> because we need to convert <math>11</math> hours into minutes.
+You will get <math>660</math>.
+Now, add <math>660</math> and <math>5</math> to get the total minutes.
+The answer is <math>\boxed{665}</math>
 {{AMC8 box|year=2016|before=First Problem|num-a=2}}
 {{MAA Notice}}

Page

Toolbox

Search

2016 AMC 8 Problems/Problem 1: Difference between revisions

Revision as of 08:59, 23 November 2016

Solution