2016 AMC 8 Problems/Problem 9: Difference between revisions
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==Solution== | ==Solution== | ||
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The prime factorization is <math>2016=2^5\times3^2\times7</math>. Since the problem is only asking us for the distinct prime factors, we have <math>2,3,7</math>. Their desired sum is then <math>\boxed{12}</math>. | |||
Revision as of 08:38, 23 November 2016
What is the sum of the distinct prime integer divisors of 
?
Solution
The prime factorization is 
. Since the problem is only asking us for the distinct prime factors, we have 
. Their desired sum is then 
.
