2014 AMC 8 Problems/Problem 10: Difference between revisions
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==Solution== | ==Solution== | ||
The seventh AMC8 would have been given in | The seventh AMC8 would have been given in 2001, when Samantha was 12. Therefore, she was born in <math>1991-12=\boxed{\textbf{(A)}~1989}</math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=9|num-a=11}} | {{AMC8 box|year=2014|num-b=9|num-a=11}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 21:35, 7 November 2016
Problem
The first AMC 
was given in 
and it has been given annually since that time. Samantha turned 
years old the year that she took the seventh AMC . In what year was Samantha born?
Solution
The seventh AMC8 would have been given in 2001, when Samantha was 12. Therefore, she was born in 
.
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing
