2002 AMC 8 Problems/Problem 13: Difference between revisions
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==Solution== | ==Solution== | ||
1^3=1 | <math>1^3=1 | ||
2^3=8 | 2^3=8 | ||
8*125=1000 | 8*125=1000 | ||
\boxed{\text{(E)}\ 1000} | \boxed{\text{(E)}\ 1000}</math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2002|num-b=12|num-a=14}} | {{AMC8 box|year=2002|num-b=12|num-a=14}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 21:25, 30 October 2016
Problem
For his birthday, Bert gets a box that holds 125 jellybeans when filled to capacity. A few weeks later, Carrie gets a larger box full of jellybeans. Her box is twice as high, twice as wide and twice as long as Bert's. Approximately, how many jellybeans did Carrie get?
Solution
.
See Also
| 2002 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
