2009 AMC 8 Problems/Problem 6: Difference between revisions

Revision as of 11:37, 2 April 2016

Problem 6

Steve's empty swimming pool will hold $24,000$ gallons of water when full. It will be filled by $4$ hoses, each of which supplies $2.5$ gallons of water per minute. How many hours will it take to fill Steve's pool?

$\textbf{(A)}\ 40 \qquad \textbf{(B)}\ 42 \qquad \textbf{(C)}\ 44 \qquad \textbf{(D)}\ 46 \qquad \textbf{(E)}\ 48$

Solution

Each of the four hoses hose fills $24,000/4 = 6,000$ gallons of water. At the rate it goes at it will take $6,000/2.5 = 2400$ minutes, or $\boxed{\textbf{(A)}\ 40}$ hours.

2009 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 5	Followed by Problem 7
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All AJHSME/AMC 8 Problems and Solutions

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	==Problem==		==Problem 6==

	Steve's empty swimming pool will hold <math> 24,000</math> gallons of water when full. It will be filled by <math> 4</math> hoses, each of which supplies <math> 2.5</math> gallons of water per minute. How many hours will it take to fill Steve's pool?		Steve's empty swimming pool will hold <math> 24,000</math> gallons of water when full. It will be filled by <math> 4</math> hoses, each of which supplies <math> 2.5</math> gallons of water per minute. How many hours will it take to fill Steve's pool?

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2009 AMC 8 Problems/Problem 6: Difference between revisions

Revision as of 11:37, 2 April 2016

Problem 6

Solution

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