2016 AMC 12B Problems/Problem 2: Difference between revisions
Created page with "==Problem== The harmonic mean of two numbers can be calculated as twice their product divided by their sum. The harmonic mean of <math>1</math> and <math>2016</math> is close..." |
|||
| Line 12: | Line 12: | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2016|ab= | {{AMC12 box|year=2016|ab=A|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:38, 21 February 2016
Problem
The harmonic mean of two numbers can be calculated as twice their product divided by their sum. The harmonic mean of 
and 
is closest to which integer?
Solution
See Also
| 2016 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing
