1988 AHSME Problems/Problem 13: Difference between revisions
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==Solution== | ==Solution== | ||
In the problem we are given that <math>\sin{(x)}=3\cos{(x)}</math>, and we want to find <math>\sin{(x)}\cos{(x)}</math>. We can divide both sides of the original equation by <math>\cos{(x)}</math> to get <cmath>\frac{\sin{(x)}}{\cos{(x)}}=\tan{(x)}=3.</cmath> | |||
We can now use right triangle trigonometry to finish the problem. | |||
<asy> | |||
pair A,B,C; | |||
A = (0,0); | |||
B = (3,0); | |||
C = (0,1); | |||
draw(A--B--C--A); | |||
draw(rightanglemark(B,A,C,8)); | |||
label("$A$",A,SW); | |||
label("$B$",B,SE); | |||
label("$C$",C,N); | |||
label("$3$",B/2,S); | |||
label("$1$",C/2,W); | |||
label("$\sqrt{10}$",(C+B)/2,NE); | |||
</asy> | |||
Since the problem asks us to find <math>\sin{(x)}\cos{(x)}</math>. | |||
<cmath>\sin{(x)}\cos{(x)}=\frac{3}{\sqrt{10}}\frac{1}{\sqrt{10}}=\frac{3}{10}.</cmath> | |||
So <math>\boxed{\textbf{(E)}\ \frac{3}{10}}</math> is our answer. | |||
== See also == | == See also == | ||
Revision as of 09:26, 2 January 2016
Problem
If
then what is
?
Solution
In the problem we are given that
, and we want to find
. We can divide both sides of the original equation by
to get
We can now use right triangle trigonometry to finish the problem.
Since the problem asks us to find
.
So
is our answer.
See also
| 1988 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
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