2006 AMC 12A Problems/Problem 4: Difference between revisions
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== Solution == | == Solution == | ||
The sum of digits is largest when the number of hours is <math>9</math> and the number of minutes is <math>59</math>. Therefore, the largest possible sum of digits is <math>9+5+9=23</math>. The answer is E. | |||
== See also == | == See also == | ||
* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] | ||
Revision as of 21:09, 11 July 2006
Problem
A digital watch displays hours and minutes with AM and PM. What is the largest possible sum of the digits in the display?
Solution
The sum of digits is largest when the number of hours is 
and the number of minutes is 
. Therefore, the largest possible sum of digits is 
. The answer is E.
