2014 AMC 8 Problems/Problem 5: Difference between revisions
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==Solution== | ==Solution== | ||
Margie can afford <math>20/4=5</math> gallons of gas. She can go <math>32\cdot5=\boxed{160}</math> miles on this amount of gas. | Margie can afford <math>20/4=5</math> gallons of gas. She can go <math>32\cdot5=\boxed{160}</math> miles on this amount of gas. So the answer is <math>\boxed{C} | ||
</math> | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=4|num-a=6}} | {{AMC8 box|year=2014|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:40, 3 November 2015
Problem
Margie's car can go 
miles on a gallon of gas, and gas currently costs $
per gallon. How many miles can Margie drive on 
worth of gas?
Solution
Margie can afford 
gallons of gas. She can go 
miles on this amount of gas. So the answer is 
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
