Art of Problem Solving

1981 AHSME Problems/Problem 1: Difference between revisions

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If <math>\sqrt{x+2}=2</math>, then <math> (x+2)^2 </math> equals: \n
If <math>\sqrt{x+2}=2</math>, then <math> (x+2)^2 </math> equals:
<math> \textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16 </math>
<math> \textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16 </math>

Revision as of 15:36, 8 February 2015

If $\sqrt{x+2}=2$, then $(x+2)^2$ equals: $\textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16$