2009 AMC 8 Problems/Problem 8: Difference between revisions
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==Problem== | ==Problem== | ||
The length of a rectangle is increased by <math> 10%</math> and the width is decreased by <math> 10%</math>. What percent of the old area is the new area? | The length of a rectangle is increased by <math> 10%</math> percent and the width is decreased by <math> 10%</math> percent. What percent of the old area is the new area? | ||
Revision as of 17:06, 31 January 2015
Problem
The length of a rectangle is increased by $10%$ (Error compiling LaTeX. Unknown error_msg) percent and the width is decreased by $10%$ (Error compiling LaTeX. Unknown error_msg) percent. What percent of the old area is the new area?
Solution
In a rectangle with dimensions 
, the new rectangle would have dimensions 
. The ratio of the old area to the new area is 
.
See Also
| 2009 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
