1966 AHSME Problems/Problem 11: Difference between revisions
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Revision as of 20:58, 14 September 2014
Problem
The sides of triangle
are in the ratio
.
is the angle-bisector
drawn to the shortest side
, dividing it into segments
and
.
If the length of
is
, then the length of the longer segment of
is:
Solution
See also
| 1966 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
[[Category:]]
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