2010 AMC 10B Problems/Problem 1: Difference between revisions

Revision as of 08:47, 6 September 2014

What is $100(100-3)-(100\cdot100-3)$ ?

$\textbf{(A)}\ -20,000 \qquad \textbf{(B)}\ -10,000 \qquad \textbf{(C)}\ -297 \qquad \textbf{(D)}\ -6 \qquad \textbf{(E)}\ 0$

$100(100-3)-(100\cdot{100}-3)=10000-300-10000+3=-300+3=\boxed{\textbf{(C)}\ -297}$ .

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 </math>
 == Solution ==
-We first expand the first term, simplify, and then compute to get an answer of <math>\boxed{\textbf{(C)}\ -297}</math>.
+<math>100(100-3)-(100\cdot{100}-3)=10000-300-10000+3=-300+3=\boxed{\textbf{(C)}\ -297}</math>.
 ==See Also==
 {{AMC10 box|year=2010|ab=B|before=First Problem|num-a=2}}
 {{MAA Notice}}