2013 AMC 8 Problems/Problem 5: Difference between revisions
Singaporean (talk | contribs) |
Singaporean (talk | contribs) |
||
| Line 5: | Line 5: | ||
==Solution== | ==Solution== | ||
The median here is | The median here is obviously less than the mean, so option (A) and (B) are out. | ||
Lining up the numbers (5, 5, 6, 8, 106), we see that the median weight is 6 pounds. | Lining up the numbers (5, 5, 6, 8, 106), we see that the median weight is 6 pounds. | ||
Revision as of 02:38, 6 March 2014
Problem
Hammie is in the 
grade and weighs 106 pounds. His quadruplet sisters are tiny babies and weigh 5, 5, 6, and 8 pounds. Which is greater, the average (mean) weight of these five children or the median weight, and by how many pounds?
Solution
The median here is obviously less than the mean, so option (A) and (B) are out.
Lining up the numbers (5, 5, 6, 8, 106), we see that the median weight is 6 pounds.
The average weight of the five kids is 
.
Therefore, the average weight is bigger, by 
pounds, making the answer 
.
See Also
| 2013 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination
