2014 AMC 12B Problems/Problem 23: Difference between revisions
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==Problem== | ==Problem== | ||
The number 2017 is prime. Let <math>S = \sum \limits_{k=0}^{62} \dbinom{2014}{k}</math>. What is the remainder when <math>S</math> is divided by 2017? | The number 2017 is prime. Let <math>S = \sum \limits_{k=0}^{62} \dbinom{2014}{k}</math>. What is the remainder when <math>S</math> is divided by 2017? | ||
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<cmath>\left(\frac{62}{2}+1 \right)^2 = 32^2 = \boxed{\textbf{(C)}\ 1024}</cmath> | <cmath>\left(\frac{62}{2}+1 \right)^2 = 32^2 = \boxed{\textbf{(C)}\ 1024}</cmath> | ||
{{AMC12 box|year=2014|ab=B|num-b=22|num-a=24}} | |||
{{MAA Notice}} | |||
Revision as of 12:33, 21 February 2014
Problem
The number 2017 is prime. Let
. What is the remainder when
is divided by 2017?
Solution
Note that
. We have for
Therefore
This is simply an alternating series of triangular numbers that goes like this:
After finding the first few sums of the series, it becomes apparent that
and
Obviously,
falls in the second category, so our desired value is
| 2014 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 22 |
Followed by Problem 24 |
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