2013 AMC 8 Problems/Problem 10: Difference between revisions
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==Solution== | ==Solution== | ||
This is very easy. To find the LCM of 180 and 594, find the prime factorization of both. | |||
The prime factorization of 180 = <math>3^2 \times 5 \times 2^2</math> | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2013|num-b=9|num-a=11}} | {{AMC8 box|year=2013|num-b=9|num-a=11}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 16:39, 27 November 2013
Problem
What is the ratio of the least common multiple of 180 and 594 to the greatest common factor of 180 and 594?
Solution
This is very easy. To find the LCM of 180 and 594, find the prime factorization of both.
The prime factorization of 180 = 
See Also
| 2013 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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