2013 AMC 8 Problems/Problem 10: Difference between revisions
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==Problem== | ==Problem== | ||
What is the ratio of the least common multiple of 180 and 594 to the greatest common factor of 180 and 594? | |||
<math>\textbf{(A)}\ 110 \qquad \textbf{(B)}\ 165 \qquad \textbf{(C)}\ 330 \qquad \textbf{(D)}\ 625 \qquad \textbf{(E)}\ 660</math> | |||
==Solution== | ==Solution== | ||
Revision as of 16:37, 27 November 2013
Problem
What is the ratio of the least common multiple of 180 and 594 to the greatest common factor of 180 and 594?
Solution
See Also
| 2013 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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