1962 AHSME Problems/Problem 18: Difference between revisions

Revision as of 21:56, 10 November 2013

A regular dodecagon ( $12$ sides) is inscribed in a circle with radius $r$ inches. The area of the dodecagon, in square inches, is:

$\textbf{(A)}\ 3r^2\qquad\textbf{(B)}\ 2r^2\qquad\textbf{(C)}\ \frac{3r^2\sqrt{3}}{4}\qquad\textbf{(D)}\ r^2\sqrt{3}\qquad\textbf{(E)}\ 3r^2\sqrt{3}$

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Revision as of 21:45, 9 November 2013 view source Fadebekun (talk \| contribs) 300 edits Created page with "==Problem== A regular dodecagon (<math>12</math> sides) is inscribed in a circle with radius <math>r</math> inches. The area of the dodecagon, in square inches, is: <math> \tex..."		Revision as of 21:56, 10 November 2013 view source Fadebekun (talk \| contribs) 300 edits →Solution Newer edit →
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	==Solution==		==Solution==
	~~"Unsolved"~~		{{solution}}