Art of Problem Solving
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1962 AHSME Problems/Problem 13: Difference between revisions

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Created page with "==Problem== <math>R</math> varies directly as <math>S</math> and inverse as <math>T</math>. When <math>R = \frac{4}{3}</math> and <math>T = \frac {9}{14}</math>, <math>S = \frac3..."
 
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==Problem==
==Problem==
<math>R</math> varies directly as <math>S</math> and inverse as <math>T</math>. When <math>R = \frac{4}{3}</math> and <math>T = \frac {9}{14}</math>, <math>S = \frac37</math>. Find <math>S</math> when <math>R = \sqrt {48}</math> and <math>T = \sqrt {75}</math>.  
<math>R</math> varies directly as <math>S</math> and inverse as <math>T</math>. When <math>R = \frac{4}{3}</math> and <math>T = \frac {9}{14}</math>, <math>S = \frac37</math>. Find <math>S</math> when <math>R = \sqrt {48}</math> and <math>T = \sqrt {75}</math>.
 
<math> \textbf{(A)}\ 28\qquad\textbf{(B)}\ 30\qquad\textbf{(C)}\ 40\qquad\textbf{(D)}\ 42\qquad\textbf{(E)}\ 60 </math>


==Solution==
==Solution==
"Unsolved"
"Unsolved"

Revision as of 21:37, 9 November 2013

Problem

$R$ varies directly as $S$ and inverse as $T$. When $R = \frac{4}{3}$ and $T = \frac {9}{14}$, $S = \frac37$. Find $S$ when $R = \sqrt {48}$ and $T = \sqrt {75}$.

$\textbf{(A)}\ 28\qquad\textbf{(B)}\ 30\qquad\textbf{(C)}\ 40\qquad\textbf{(D)}\ 42\qquad\textbf{(E)}\ 60$

Solution

"Unsolved"