Art of Problem Solving
During AMC 10A/12A testing, the AoPS Wiki is in read-only mode and no edits can be made.

2008 AMC 8 Problems/Problem 13: Difference between revisions

Gina (talk | contribs)
Nathan wailes (talk | contribs)
No edit summary
Line 15: Line 15:
==See Also==
==See Also==
{{AMC8 box|year=2008|num-b=12|num-a=14}}
{{AMC8 box|year=2008|num-b=12|num-a=14}}
{{MAA Notice}}

Revision as of 00:38, 5 July 2013

Problem

Mr. Harman needs to know the combined weight in pounds of three boxes he wants to mail. However, the only available scale is not accurate for weights less than $100$ pounds or more than $150$ pounds. So the boxes are weighed in pairs in every possible way. The results are $122$, $125$ and $127$ pounds. What is the combined weight in pounds of the three boxes?

$\textbf{(A)}\ 160\qquad \textbf{(B)}\ 170\qquad \textbf{(C)}\ 187\qquad \textbf{(D)}\ 195\qquad \textbf{(E)}\ 354$

Solution

Each box is weighed twice during this, so the combined weight of the three boxes is half the weight of these separate measures

\[\frac{122+125+127}{2} = \frac{374}{2} = \boxed{\textbf{(C)}\ 187}\]

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: Unable to save thumbnail to destination