2000 AIME I Problems/Problem 1: Difference between revisions
Danielguo94 (talk | contribs) |
No edit summary |
||
| Line 19: | Line 19: | ||
[[Category:Introductory Number Theory Problems]] | [[Category:Introductory Number Theory Problems]] | ||
{{MAA Notice}} | |||
Revision as of 18:48, 4 July 2013
Problem
Find the least positive integer
such that no matter how
is expressed as the product of any two positive integers, at least one of these two integers contains the digit
.
Solution
If a factor of
has a
and a
in its prime factorization, then that factor will end in a
. Therefore, we have left to consider the case when the two factors have the
s and the
s separated, in other words whether
or
produces a 0 first.
|
|
|
and so on, until,
|
We see that
generates the first zero, so the answer is
.
See also
| 2000 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing