Art of Problem Solving

2009 AMC 8 Problems/Problem 8: Difference between revisions

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\textbf{(D)}\  101  \qquad
\textbf{(D)}\  101  \qquad
\textbf{(E)}\  110</math>
\textbf{(E)}\  110</math>
==Solution==
In a rectangle with dimensions <math>10 \times 10</math>, the new rectangle would have dimensions <math>11 \times 9</math>. The ratio of the old area to the new area is <math>99/100 = \boxed{\textbf{(B)}\ 99}</math>.


==See Also==
==See Also==
{{AMC8 box|year=2009|num-b=7|num-a=9}}
{{AMC8 box|year=2009|num-b=7|num-a=9}}

Revision as of 15:30, 25 December 2012

Problem

The length of a rectangle is increased by $10%$ (Error compiling LaTeX. Unknown error_msg) and the width is decreased by $10%$ (Error compiling LaTeX. Unknown error_msg). What percent of the old area is the new area?


$\textbf{(A)}\  90  \qquad \textbf{(B)}\   99  \qquad \textbf{(C)}\   100  \qquad \textbf{(D)}\   101  \qquad \textbf{(E)}\   110$

Solution

In a rectangle with dimensions $10 \times 10$, the new rectangle would have dimensions $11 \times 9$. The ratio of the old area to the new area is $99/100 = \boxed{\textbf{(B)}\ 99}$.

See Also

2009 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions