2003 AMC 8 Problems/Problem 6: Difference between revisions
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==Problem== | ==Problem== | ||
Given the areas of the three squares in the figure, what is the area of the interior triangle? | Given the areas of the three squares in the figure, what is the area of the interior triangle? | ||
<asy> | |||
draw((0,0)--(-5,12)--(7,17)--(12,5)--(17,5)--(17,0)--(12,0)--(12,-12)--(0,-12)--(0,0)--(12,5)--(12,0)--cycle,linewidth(1)); | |||
label("$25$",(14.5,1),N); | |||
label("$144$",(6,-7.5),N); | |||
label("$169$",(3.5,7),N); | |||
</asy> | |||
<math>\mathrm{(A)}\ 13 \qquad\mathrm{(B)}\ 30 \qquad\mathrm{(C)}\ 60 \qquad\mathrm{(D)}\ 300 \qquad\mathrm{(E)}\ 1800</math> | <math>\mathrm{(A)}\ 13 \qquad\mathrm{(B)}\ 30 \qquad\mathrm{(C)}\ 60 \qquad\mathrm{(D)}\ 300 \qquad\mathrm{(E)}\ 1800</math> | ||
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The sides of the squares are <math> 5, 12 </math> and <math> 13 </math> for the square with area <math> 25, 144 </math> and <math> 169 </math>, respectively. The legs of the interior triangle are <math> 5 </math> and <math> 12 </math>, so the area is <math> \frac{5 \times 12}{2}=\boxed{\mathrm{(B)}\ 30} </math> | The sides of the squares are <math> 5, 12 </math> and <math> 13 </math> for the square with area <math> 25, 144 </math> and <math> 169 </math>, respectively. The legs of the interior triangle are <math> 5 </math> and <math> 12 </math>, so the area is <math> \frac{5 \times 12}{2}=\boxed{\mathrm{(B)}\ 30} </math> | ||
==See Also== | |||
{{AMC8 box|year=2003|num-b=5|num-a=7}} | {{AMC8 box|year=2003|num-b=5|num-a=7}} | ||
Revision as of 02:41, 24 December 2012
Problem
Given the areas of the three squares in the figure, what is the area of the interior triangle?
![[asy] draw((0,0)--(-5,12)--(7,17)--(12,5)--(17,5)--(17,0)--(12,0)--(12,-12)--(0,-12)--(0,0)--(12,5)--(12,0)--cycle,linewidth(1)); label("$25$",(14.5,1),N); label("$144$",(6,-7.5),N); label("$169$",(3.5,7),N); [/asy]](http://latex.artofproblemsolving.com/3/7/2/372ee1f13836b7ad774c0aa23e598d4f8b07cbb6.png)
Solution
The sides of the squares are 
and 
for the square with area 
and 
, respectively. The legs of the interior triangle are 
and 
, so the area is 
See Also
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
