2007 AMC 8 Problems/Problem 3: Difference between revisions

Revision as of 12:10, 9 December 2012

What is the sum of the two smallest prime factors of $250$ ?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

We prime factor 250.

We get $2 * 5 * 5 * 5$

The two smallest are $2$ and $5$ .

So, $2 + 5 = 7$

The answer is $\boxed{\textbf{(C)}\ 7}$

2007 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

@@ Line 15: / Line 15: @@
 So, <math>2 + 5 = 7</math>
-The answer is <math>\boxed{C}</math>
+The answer is <math> \boxed{\textbf{(C)}\ 7} </math>
 ==See Also==
 {{AMC8 box|year=2007|num-b=2|num-a=4}}