2007 AMC 8 Problems/Problem 15: Difference between revisions
Created page with '== Problem == Let <math>a, b</math> and <math>c</math> be numbers with <math>0 < a < b < c</math>. Which of the following is impossible? <math>\mathrm{(A)} \ a + c < b \qquad …' |
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Therefore, the answer is <math>\boxed{A}</math> | Therefore, the answer is <math>\boxed{A}</math> | ||
==See Also== | |||
{{AMC8 box|year=2007|num-b=14|num-a=16}} | |||
Revision as of 22:42, 12 November 2012
Problem
Let 
and 
be numbers with 
. Which of the following is
impossible?
Solution
According to the given rules,
Every number needs to be positive.
Since is always greater than 
,
adding a positive number (
) to will always make it greater than .
Therefore, the answer is 
See Also
| 2007 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 14 |
Followed by Problem 16 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
