2007 AMC 8 Problems/Problem 3: Difference between revisions

Revision as of 14:06, 12 November 2012

What is the sum of the two smallest prime factors of $250$ ?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

We prime factor 250.

We get $2 * 5 * 5 * 5$

The two smallest are $2$ and $5$ .

So, $2 + 5 = 7$

The answer is $\boxed{C}$

2007 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
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All AJHSME/AMC 8 Problems and Solutions

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 The answer is <math>\boxed{C}</math>
+==See Also==
+{{AMC8 box|year=2007|before=First<br />Question|num-a=2}}