1994 AJHSME Problems/Problem 14: Difference between revisions
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Two children at a time can play pairball. For <math>90</math> minutes, with only two children playing at time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is | Two children at a time can play pairball. For <math>90</math> minutes, with only two children playing at time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is | ||
where is the anwser ? | |||
<math>\text{(A)}\ 9 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 18 \qquad \text{(D)}\ 20 \qquad \text{(E)}\ 36</math> | <math>\text{(A)}\ 9 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 18 \qquad \text{(D)}\ 20 \qquad \text{(E)}\ 36</math> | ||
Revision as of 19:24, 8 November 2012
Problem
Two children at a time can play pairball. For 
minutes, with only two children playing at time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is
where is the anwser ?
