2010 AMC 8 Problems/Problem 7: Difference between revisions

Revision as of 23:28, 3 November 2012

We need:

4 Pennies, 1 Nickel, 2 Dimes, and 3 Quarters

$4+1+2+3 = \boxed{\textbf{(B) } 10}$

2010 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

@@ Line 7: / Line 7: @@
 <math>4+1+2+3 = \boxed{\textbf{(B) } 10}</math>
+==See Also==
+{{AMC8 box|year=2010|num-b=4|num-a=6}}