2010 AMC 8 Problems/Problem 7: Difference between revisions
Created page with "We need: 4 Pennies, 1 Nickel, 2 Dimes, and 2 Quarters Making 10 coins so the answer is B." |
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2 Dimes, and | 2 Dimes, and | ||
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<math>4+1+2+3 = \boxed{\textbf{(B) } 10}</math> | |||
Revision as of 23:27, 3 November 2012
We need:
4 Pennies, 1 Nickel, 2 Dimes, and 3 Quarters