1950 AHSME Problems/Problem 40: Difference between revisions
Mrdavid445 (talk | contribs) Created page with "==Problem== The limit of <math> \frac {x^2\minus{}1}{x\minus{}1}</math> as <math>x</math> approaches <math>1</math> as a limit is: <math>\textbf{(A)}\ 0 \qquad \textbf{(B)}\ \t..." |
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\textbf{(D)}\ 2 \qquad | \textbf{(D)}\ 2 \qquad | ||
\textbf{(E)}\ 1</math> | \textbf{(E)}\ 1</math> | ||
==Solution== | |||
{{solution}} | |||
==See Also== | |||
{{AHSME 50p box|year=1950|num-b=39|num-a=41}} | |||
[[Category:Introductory Algebra Problems]] | |||
Revision as of 07:39, 29 April 2012
Problem
The limit of $\frac {x^2\minus{}1}{x\minus{}1}$ (Error compiling LaTeX. Unknown error_msg) as 
approaches 
as a limit is:
Solution
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See Also
| 1950 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 39 |
Followed by Problem 41 | |
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| All AHSME Problems and Solutions | ||
