1950 AHSME Problems/Problem 19: Difference between revisions
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{{AHSME box|year=1950|num-b=18|num-a=20}} | {{AHSME 50p box|year=1950|num-b=18|num-a=20}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
Revision as of 07:33, 29 April 2012
Problem
If 
men can do a job in 
days, then 
men can do the job in:
Solution
The number of men is inversely proportional to the number of days the job takes. Thus, if men can do a job in days, we have that it will take 
days for 
man to do the job. Thus, 
men can do the job in 
days and our is 
See Also
| 1950 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
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