Triangle Inequality: Difference between revisions

Revision as of 11:52, 25 June 2006

In a nondegenerate triangle $\displaystyle ABC$ :

$\displaystyle AB + BC > AC$

$\displaystyle BC + AC > AB$

$\displaystyle AC + AB > BC$

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Revision as of 09:34, 25 June 2006 view source Dschafer (talk \| contribs) 48 edits Added math tags ← Older edit		Revision as of 11:52, 25 June 2006 view source ComplexZeta (talk \| contribs) editor 240 edits mNo edit summary Newer edit →
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	In a ~~non-trivial~~ triangle <math>\displaystyle ABC</math>:		In a nondegenerate triangle <math>\displaystyle ABC</math>:

	<math>\displaystyle AB + BC > AC</math>		<math>\displaystyle AB + BC > AC</math>