2012 AMC 12B Problems/Problem 2: Difference between revisions
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==Solution== | ==Solution== | ||
If the radius is 5, then the width is 10, hence the length is 20. | If the radius is <math>5</math>, then the width is <math>10</math>, hence the length is <math>20</math>. <math>10\times20=200</math>, <math>\boxed{\text{E}}</math> | ||
Revision as of 15:02, 24 February 2012
Problem
A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to it's width is 2:1. What is the area of the rectangle
Solution
If the radius is 
, then the width is 
, hence the length is 
. 
, 
