2011 AMC 12A Problems/Problem 2: Difference between revisions
fixed my latex |
m <asy> by binomial-theorem |
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== Problem == | == Problem == | ||
There are <math>5</math> coins placed flat on a table according to the figure. What is the order of the coins from top to bottom? | There are <math>5</math> coins placed flat on a table according to the figure. What is the order of the coins from top to bottom? | ||
<asy> | |||
size(100); defaultpen(linewidth(.8pt)+fontsize(8pt)); | |||
draw(arc((0,1), 1.2, 25, 214)); | |||
draw(arc((.951,.309), 1.2, 0, 360)); | |||
draw(arc((.588,-.809), 1.2, 132, 370)); | |||
draw(arc((-.588,-.809), 1.2, 75, 300)); | |||
draw(arc((-.951,.309), 1.2, 96, 228)); | |||
label("$A$",(0,1),NW); label("$B$",(-1.1,.309),NW); label("$C$",(.951,.309),E); label("$D$",(-.588,-.809),W); label("$E$",(.588,-.809),S);</asy> | |||
<math> | <math> | ||
\textbf{(A)}\ (C, A, E, D, B) \qquad | \textbf{(A)}\ (C, A, E, D, B) \qquad | ||
| Line 12: | Line 19: | ||
By inspection, the answer is <math>\textbf{(E)}</math>. | By inspection, the answer is <math>\textbf{(E)}</math>. | ||
== See also == | == See also == | ||
{{AMC12 box|year=2011|num-b=1|num-a=3|ab=A}} | {{AMC12 box|year=2011|num-b=1|num-a=3|ab=A}} | ||
[[Category:Introductory Combinatorics Problems]] | |||
Revision as of 19:29, 18 August 2011
Problem
There are
coins placed flat on a table according to the figure. What is the order of the coins from top to bottom?
Solution
By inspection, the answer is
.
See also
| 2011 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |